Physics, asked by sudhasingh6785, 9 months ago

a point is 10 cm away from a point charge 10 ^-9c.find the magnitude of electric field intensity at that point​

Answers

Answered by sumitpanigrahi95
5

Answer:

Given, q=10^-9, r=10cm= 1/10m

E = 9(10^9)[10^-9/(1/10)^2]

E= 9(10^2)

E= 900N/C

Answered by Jyothirmai2007Putta
1

Answer:

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