Math, asked by vy09011996, 5 months ago

A point is in Quadrant-III and on the Unit Circle. If its x-coordinate is -4 / 5, what is the y-coordinate of the point?​

Answers

Answered by luckysaga202
0

Answer:

-4/5

Step-by-step explanation:

because in 3rd quadrant, y-axis coordinates are also -ve

Answered by visala21sl
0

Answer:

y coordinate = sin(x) = ±\frac{\frac{3}{5} }{1} =  ±\frac{3}{5}

Step-by-step explanation:

In a unit circle

X coordinate = cos(x)

y coordinate = sin(x)

If cos(x) = -\frac{4}{5}

the hypotenuse is 1 and the adjacent leg is  -\frac{4}{5}.

then the other leg is ±\sqrt{1^{2}-(\frac{4}{5} )^{2}  } = ±\sqrt{1-\frac{16}{25} } = ±\sqrt{\frac{9}{25} } = ±\frac{3}{5}

The opposite leg is  ±\frac{3}{5}

y coordinate = sin(x) = ±\frac{\frac{3}{5} }{1} =  ±\frac{3}{5}

Since it is in the third quadrant, both x and y are negative.

then sin(x) is negative or -\frac{3}{5}

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