Question

A point moves along a circle with a velocity v = at , where a = 0.50 m / s^2 . find the total acceleration of the point at the moment when it has covered the nth ( n = 0.10 ) fraction of the circle after beginning of the motion .
1. 0.8 m / s^2
2. 0.3 m / s^2
3. 0.2 m / s^2
4. 0.50 m / s^2​

Answer 1

Explanation:

Thevelocityoftheparticlev=at

So,

dt

dv

=w

t

=a−−−−−−−(1)

andw

R

=

R

v

2

=

R

a

2

t

2

(usingv=at)−−−−−(2)

froms=∫vdt

2πRη=a∫

0

t

vdt=

2

1

at

2

So,

a

4πη

=

R

t

2

−−−−−−−(3)

fromequation(2)and(3)

w

R

=4πaη

then,w=

w

t

2

+w

π

2

=

a

2

+(4πaη)

2

=a

1+16π

2

η

2

=0.8m/