a point moves in a straight line it's displacement x with time tis x²=1+t² find accelerationat time t
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Answer:1/x3
Explanation:
taking its differentiation,
2x*(dx/dt)=2t
x*(dx/dt)=t
again taking differentiation for acceleration,
x*(d2x/dt2) + (dx/dt)2 = 1
x*(d2x/dt2) = 1 – (dx/dt)2
x*(d2x/dt2) = 1 – (t/x)2 (because x*(dx/dt)=t)
(d2x/dt2) = (1 – (t/x)2)/x
(d2x/dt2) = 1/x – t2/x3
put t2 = x2 -1
(d2x/dt2) = 1/x3
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