Math, asked by raviralayuvaraj, 2 months ago

a point moves in such a way that its distance from a fixed straight line is always 1.5 times the distance from a fixed point which is 45 away from the fixed straight line. Draw the locus of the point also draw a tangent and normal at a point 45 from the fixed point​

Answers

Answered by Anonymous
4

Step-by-step explanation:

distance from a fixed point 'F' to a fixed straight line is always a constant. This ratio ... Conic is hyperbola since 1.5 is greater than one (e>1). 3. ... always equal to its distance from Directrix.

krishnpriya ❤️

Answered by akshita4595
0

Answer:

The locus of the point can be represented as an ellipse with its center at the fixed point and with semi-axes equal to 45 and 1.5 * 45 = 67.5 units.

The focus of the ellipse is the fixed point and the fixed straight line. The distance between the foci is 45 units, and the sum of the distances from any point on the ellipse to the focus is equal to 90 units. The tangent at a point 45 units away from the fixed point will be perpendicular to the line connecting the point to the fixed point, and the normal will be perpendicular to the tangent and hence parallel to the line connecting the point to the fixed point.

Here is a description of how you could sketch the ellipse:

Draw a line to represent the fixed straight line.

Draw a point to represent the fixed point, 45 units away from the fixed line.

Draw a circle centered at the fixed point with a radius of 45 units.

Draw the major axis of the ellipse as the line connecting the intersections of the circle with the fixed straight line.

Draw the minor axis of the ellipse as a line perpendicular to the major axis and passing through the fixed point.

Draw the ellipse by tracing a continuous path along the perimeter that's equidistant from the focus.

To learn more about Ellipses, click here

https://brainly.in/question/61482

To learn more about tangent and normal, click here

https://brainly.in/question/15145463

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