Question

- A point moves in x-y plane according to the law x = 3 cos 4t and y = 3 (1 - sin 4t). The distance travelled by the particle in 2 sec is (where x and y are in meters)

(a) 48 m
(b) 24 m
(c) 48√2 m
(d) 24√2 m​

Answer 1

Answer:

(b) 24 m

Explanation:

V = √v1 + v2

= (-12 sin × 4t)^2 + (-12 cos × 4t)^2

= 12 m/s

Speed is constant,

Distance = Speed × Time

= 12 m/s × 2 second

= 24 m