a point moves so that it always at a distance of 6 units from the point (1,-4).find it locus
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Answered by
2
♧♧HERE IS YOUR ANSWER♧♧
Let, the moving point be (x, y).
Then,
√[ (x - 1)² + (y + 4)² ] = 6
Squaring, we get :
(x - 1)² + (y + 4)² = 6²,
which is the required locus of (x, y) point. It is a circle, whose centre is at (1, -4) and radius is 6 units.
♧♧HOPE THIS HELPS YOU♧♧
Let, the moving point be (x, y).
Then,
√[ (x - 1)² + (y + 4)² ] = 6
Squaring, we get :
(x - 1)² + (y + 4)² = 6²,
which is the required locus of (x, y) point. It is a circle, whose centre is at (1, -4) and radius is 6 units.
♧♧HOPE THIS HELPS YOU♧♧
Answered by
21
hay!!
dear user
According to the question we know that let moving point (x, y)
Then,
(x-1)²+(y+4)²=6²
so, the circle whose center is (1,4) and radius is 6 unit
I hope it's help you
dear user
According to the question we know that let moving point (x, y)
Then,
(x-1)²+(y+4)²=6²
so, the circle whose center is (1,4) and radius is 6 unit
I hope it's help you
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