Question

a point o is the interior of ∆ ABC . prove that 2(OA+OB+OC) >AB+BC+AC.​

Answer 1

Answer:

$</p><p>{ \huge\fbox \pink {Q}\fbox \blue {u} \fbox \purple {e} \fbox \green{s} \fbox \red {t} \fbox \orange {i} \fbox{o} \fbox \gray{n} }Question</p><p>$

$┌⋆Solution⋆┐</p><p>$

Step-by-step explanation:

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