a point O marked on the surface of glass sphere of diameter 20cm is viewed through a glagg opposite to the point O.If RI=1.5 find the position of the image
Answers
The refraction of light occurs when light travels from medium of one refractive index to another refractive index .
According to the lens formula for refraction between two surfaces of different refractive index .
=> μ2/v - μ1/u = (μ2-μ1)/R
where, μ2 = refractive index of air = 1
μ1 = refractive index of glass = 1.5
R = radius of curvature of sphere
v = image distance
u = object distance = - 20 cm
=> μ2/v - μ1/u = (μ2-μ1)/R
=> 1/v - 1.5/(-20) = (1-1.5)/(-10)
=> 1/v = 0.5/10 - 1.5/20
=> 1/v = - 1/40
=> v = - 40 cm
Thus, position of image from centre of sphere = 40 - 10
= 30 cm
Explanation:
use formula
RHS /image distance - LHS / object distance = RHS - LHS / radius of curvature