Question

a point object in air is situated on the principal axis of convex glass surface 15 cm from its pole .The RI of glass is1.5 and radius of curvature of spherical surface is 30cm .Then the image distance is​

Answer 1

Answer:

ANSWER

Given,

Refractive index, μ=1.5

Radius of curvature, R=20cm

Object distance, u=100cm

Image distance, v=?

We know

v

μ

2

−

u

μ

1

=

R

μ

2

−μ

1

μ

2

=1.5

μ

1

=1

⇒

v

1.5

+

100

1

=

20

1.5−1

⇒

v

1.5

=

20

0.5

−

100

1

⇒

v

1.5

=

200

3

⇒ v=

3

200

×1.5

v=100cm

Explanation:

hope it is helpful