a point object is placed at a distance of 10cm and its real image is formed at a distance of 30cm from a concave mirror of the object is moved by 0.2cm towards the mirror, the image will shift by about.
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Answered by
0
=9.9cm
Again
f
1
=
u
1
1
+
v
1
1
f
1
−
u
1
1
=
v
1
1
v
1
1
=
20
3
−
(−9.9)
1
v
1
=20.4cm=20.4cm−20cm=0.4cm
v=
3600
9×1600
=4cm/s
Answered by
0
Answer:
the image shift about 0.6
Explanation:
if the distance of a real image fromed 10cm the image formed at distance of 30cm then in 1cm in mirror the distance is 3cm if it 2cm in the mirror it take 6cm so the ans is 0.6
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