Question

A point object is placed at a distance of 20cm from convex mirror of focal length 20 cm, find where the image will be formed?

Answer 1

Answer:

$\boxed{\mathfrak{Image \ distance \ (v) = 10 \ cm}}$

Given:

Image distance (u) = -20 cm

Focal length (f) = 20 cm

To Find:

Image distance (v)

Explanation:

Mirror formula:

$\boxed{ \bold{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }}$

Substituting value of u & f in the formula:

$\sf \implies \frac{1}{v} + ( \frac{1}{ - 20} ) = \frac{1}{20} \\ \\ \sf \implies \frac{1}{v} - \frac{1}{20} = \frac{1}{20} \\ \\ \sf \implies \frac{1}{v} = \frac{1}{20} + \frac{1}{20} \\ \\ \sf \implies \frac{1}{v} = \frac{1 + 1}{20} \\ \\ \sf \implies \frac{1}{v} = \frac{2}{20} \\ \\ \sf \implies \frac{1}{v} = \frac{1}{10} \\ \\ \sf \implies v = 10 \: cm$

$\therefore$

Image distance (v) = 10 cm

Answer 2

Answer:

Gɪᴠᴇɴ, ғ=20ᴄᴍ,ᴜ=−20ᴄᴍ,ᴠ=?

As, 1/ғ = 1/ᴠ + 1/ᴜ

1/ᴠ= 1/ғ +1/ᴜ

1/ᴠ= 1/20 +1/20

1/ᴠ = 2/20

ᴠ=10ᴄᴍ

Sᴏ, ᴛʜᴇ ᴅɪsᴛᴀɴᴄᴇ ᴏғ ᴛʜᴇ ɪᴍᴀɢᴇ ғʀᴏᴍ ᴛʜᴇ ᴘᴏʟᴇ ᴏғ ᴛʜᴇ ᴍɪʀʀᴏʀ ɪs 10ᴄᴍ.

Explanation:

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