Question

. A point-object is placed in air at 40 cm from a concave
spherical surface of radius of curvature 20 cm and
refractive index 1.5. Locate the image.​

Answer 1

Answer:

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Answer 2

Answer:

$\huge\underline\mathcal\red{★Answer:}$

$\implies$Given object distance u=40 cm, radius of curvature R=20 cm

★refractive index:

$n_{1}$=1.5

$n_{2}$=1

Now making use of the relation :

$\frac{ n_{2} }{v}$- $\frac{ n_{1} }{u}$= $\frac{ n_{2} -n_{1} }{r}$

v= 1.5×-20 = -30