Question

A point object O is placed in air. A spherical (convex) boundary of radius of curvature 1.0 m
separates two media. AB is principal axis. The refractive index above AB is 1.6 and below AB is 2.0.
The separation between the images formed due to refraction at spherical surface is:
1.6
B
2m
2.0
(1) 12 m
(2) 20 m
(3) 14 m
(4) 10 m​

Answer 1

Answer:

The separation between the images formed due to refraction at spherical surface is 12 m

Explanation:

According to the problem the refractive index above AB is 1.6

he refractive index below AB is 2.0

Now for the refractive index above AB:

1.6/a1−1.0/−2 =1.6−1.0/+10   [ where the radius of the curvature = 1.0 m]

a1=16cm

Now for the refractive index below AB:

2.0/a2−1.0/−2=2.0−1.0/+10

a2=4m  

Therefore  the  separation between the images formed due to refraction at spherical surface is

a1−a2

     = 12 m