a point of wheel cover half of rotation radius =1m
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Situation is shown in figure. Let initially point of contact with ground is P , then after half revolution, point shift to top of the wheel at P' as you can see in figure.
so, displacement = final position - initial position
= PP' [ see figure ]
= √{length of half revolution² + diameter ²}
length of half revolution = πr = 3.14 × 1 = 3.14 m
diameter = 2r = 2 × 1 = 2m
so, displacement = √{3.14² + 2²}
= √{9.8596 + 4}
= √{13.8596} = 3.72 m
hence, The magnitude of the displacement of the point of the wheel initially in contact with ground is 3.72m
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