Question

a point on a flywheel of radius 0.5m has a uniform linear acceleration of 2 m/s². it's angular acceleration is​

Answer 1

Solution :

⏭ Given:

✏ Radius of flywheel = 0.5m

✏ Linear acceleration = 2m/s^2

⏭ To Find:

✏ Angular acceleration of flywheel

⏭ Formula:

✏ Relation between linear acceleration, radius and angular acceleration is given by

• a = r × α

⏭ Terms indication:

✏ a denotes linear acceleration

✏ r denotes radius of circular path

✏ α denotes angular acceleration

⏭ Calculation:

✏ 2 = 0.5 × α

✏ α = 2 / 0.5

✏ α = 4 rad/s^2

⏭ Additional information:

• Angular acceleration is axial vector quantity.
• Linear acceleration is also vector quantity.
• In a uniform circular motion, the acceleration vector is directly towards the centre.
• For a body moving with a constant angular velocity, the angular acceleration is zero.

Answer 2

$\huge \mathtt{ \fbox{Solution :)}}$

Given ,

Linear acceleration (a) = 2 m/s²

Radius of the flywheel (r) = 0.5 m

We know that , the relation b/w linear and angular acceleration is given by

$\large \mathtt{ \fbox{Linear \: acceleration = radius × angular \: acceleration }}$

Thus ,

➡2 = 0.5 × angular acceleration

➡angular acceleration = 2/0.5

➡angular acceleration = 4 rad/s²

Hence , the angular acceleration is 4 rad/s²

_____________ Keep Smiling ☺