Math, asked by pragathisaripudi09, 9 months ago

a point on line x-y+1=0 at a distance 2√2 from the point (1,2) is

Answers

Answered by Joianaverma

0

Answer:

2√445-=°f

Step-by-step explanation:

35|•√78182+×88

557*66

5378-123√

=2√445-=°f

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