Question

A point on the ground is 80 m away from the foot of the tower. From this point angle of elevation of the tower is found to be 60.Find the height of the tower.​

Answer 1

Answer:

ANSWER

In ΔADC

tan30

o

=

AC

DC

3

1

=

d

h

........(1)

d=

3

h

→d=

3

×10

3

=30m

In ΔBCD

tan60

o

=

BC

DC

3

=

d−20

h

.......(2)

on solving equation (1) & (2)

3

=

3

h−20

h

⇒3h−20

3

=h

2h=20

3

h=10

3

m

height of tower.