A point on the rim of a flywheel of radius 0.5 m
moves with linear speed 5 msl. Calculate the
angular speed of the flywheel.
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Answer:
The angular velocity omega is the rate of change of the angular position, or omega=d(theta)/dt, where theta is the angle. On revolution is 2*pi radians~6.28 radians. So,
120 revloutions/per minute is 6.28*120 radians/minute~754 radians/minute. The radius of the flywheel is not necessary. But the tangential velocity of the edge of the flywheel, at radius r=2 m, is given by
v=r*omega=2*754=1508 m/minute~1510 m/minute
Explanation:
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