Question

A point on x-axis which is equidistance
from P(5, 4) and Q(-2, 3) is :
(a) (4, 0)
(b) (7,0)
(c) (2, 0)
(d) (8,0)​

Answer 1

Answer:

(c) (2,0)

Step-by-step explanation:

Let the required point be A(x,0).

AP=AQ

√[(x-5)^2+(0-4)^2]=√[(x+2)^2+(0-3)^2]

Squaring both sides,

x^2+25-10x+16=x^2+4+4x+9

28=14x

So, x=2

Required point (2,0). (c)

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