Question

A point p(2,-1) is equidistant from the points (a,7) and(-3,a) find a

Answer 1

p (2,-1) is equidistant from A (a,7) and B (-3, a)
hence ,
PA =PB
take square both side
PA^2 =PB^2

use distance formula
PA=root {(a -2)^2 +(7+1)^2}
PA^2 =(a-2)^2 + (8)^2

in the same way ,
PB^2 =(-5)^2 +(a+1)^2

so ,
(-5)^2 +(a+1)^2 =(8)^2 +(a-2)^2

a^2 + 2a + 1 -a^2 +4a -4 =64- 25

6a -3 =39

6a =42

a =7 (ans )

Answer 2

Answer:

Hope it helps you