Question

A point P(2,-1) is equidistant from the points A(m,7) and B(-3,m) . Find m ?

Answer 1

P (2,-1) is equidistant from A (a,7) and B (-3, a) 
hence ,
PA =PB
take square both side 
PA^2 =PB^2 

use distance formula 
PA=root {(a -2)^2 +(7+1)^2}
PA^2 =(a-2)^2 + (8)^2 

in the same way ,
PB^2 =(-5)^2 +(a+1)^2

so ,
(-5)^2 +(a+1)^2 =(8)^2 +(a-2)^2 

a^2 + 2a + 1 -a^2 +4a -4 =64- 25

6a -3 =39

6a =42

a =7 (ans )

i think it helps u....
but i can't do dis by my own.......

Answer 2

Hope it may help you !!!!!