Question

A point p is 23 cm away from the centre of a circle and the length of tangent drawn from p to the circle is 20 cm find the radius of the circle​

Answer 1

Answer:

Radius=11.35cm

Step-by-step explanation:

(OP)^2=(AP)^2-(OA)^2

(23)^2=(20)^2-(OA)^2

529=400-(OA)^2

129=(OA)^2

OA=root of 129

OA=11.35cm

Radius=11.35cm

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Answer 2

Answer:

Radius = √129 cm

Step-by-step explanation:

Let OA be the radius of a circle with center O.

We know that radius is always perpendicular to the tangent.

∴ Triangle OAP is a right-angled triangle.

∴ (OP)² = (OA)² + (PA)²

(23)² = (OA)² + (20)²

529 = (OA)² + 400

529 - 400 = (OA)²

129 = (OA)²

√129 cm = OA

∴ Radius of the circle is √129 cm.