Question

a point P is 250 m before the sea level and another point Q is 521 m above the sea level find distance between these two point​

Answer 1

Answer:the distance between these two points = 250

Answer 2

Answer:

x= 671.70 m

Step-by-step explanation:

Point  p = 250 m (before)

Point Q = 521 m (above sea )(perpendicular = 90⁰)

So, point P,Q and R(imaginary ) forms a Right angled Triangle

And PQ is hypotenuse

PR and QR are the legs

BY pythagoras theorem ;

$PR^2 + QR^2 = PQ^2$

$250 ^{2}+ 591 ^{2} = x^2\\62500+349281 =x^2\\411781 =x^2\\Taking Square root on both sides\\x = 641.701644068\\x= 641.70 m$