Question

a point p is 26cm away from the centre o of a circle and the length pt ,of the tangent drawn p to the circle is 10 cm. find the radius of the circle

Answer 1

Join the points O,P,T .It forms like a triangle whose hypotenuse is26cm altitude is 10cm then
Base=26*26_10*10=576
Radius =root of 576 i.e;24

Answer 2

The radius of the circle is 24 cm.

Given:

From the given information, we can get the diagram given below,

To find:

Radius = ?

Solution:

Join the points O, P, and T.

We get a right angled triangle, $\Delta OTP$

By using Pythagoras theorem, we get,

$OP^{2} = OT^{2} + TP^{2}$

$OT^{2} = OP^{2} - TP^{2}$

$OT^{2} = 26^{2} - 10^{2}$

$OT^{2} = 676 - 100$

$OT^{2} = 576$

$\Rightarrow OT=24 \ \mathrm{cm}$