Question

A point p is 26cm away from the centre of the circle and the length of thr tangent drawn from p to the circle is 24cm . Find the radius

Answer 1

(OP)^2=(PA)^2-(OA)^2
(26)^2=(24)^2-(OA)^2
672=576-(OA)^2
100=(OA)^2
OA=10cm.
So,radius is 10cm.

Answer 2

Answer:

The radius of the circle is 10 cm.

Step-by-step explanation:

Given : A point p is 26cm away from the centre of the circle and the length of thr tangent drawn from p to the circle is 24cm .

To find : The radius?

Solution :

Let r be the radius and O be the center of a  circle on which PT is a tangent from point P.

In right angled triangle OTP.

Applying Pythagoras theorem,

$OT^2+PT^2=OP^2$

$r^2+24^2=26^2$

$r^2=676-576$

$r^2=100$

$r= 10$

Therefore, The radius of the circle is 10 cm.