Question

A point P is at a distance of root 10 from the point (4 ,3) find the coordinates of point P if its ordinate is twice of its abscissa

Answer 1

Answer:

Let the abscissa be x and ordinate be 2x then we have,by distance formula,

= bt squaring both sides of distance formula we get

=(4-a) ^2 +(3-2a) ^2=10

=16+a^2-8a+9+4a^2-12a=10

=5a^2-20a+25=10

=5a^2-20a= -15

=5a^2-20a+15=0

=divide whole equation by 5 we get,

=a^2-4a+3=0

=a^2-3a-a+3=0

=a(a-3)-1(a-3) =0

=(a-3) (a-1)=0

=a=3 or a=1

hence, the coordinate of point P is P(3, 6) or P(1, 2)