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A point P is located outside the circle with centre O. A tangent from point P
touches the circle at A and a secant from P cuts the circle at B and C respectively.
PA =12cm PC= 16cm. Find the length of chord BC.
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answer : 7
PA=12 PC=16 SO PB= 9 SO BC = 16-9 = 7
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Solution :-
given that,
→ PA = Tangent = 12 cm
→ PC = Secant = 16 cm
So,
→ PA² = PB * PC { Secant tangent theorem }
→ 12² = PB * 16
→ PB = 144/16
→ PB = 9
So,
→ BC = PC - PB
→ BC = 16 - 9
→ BC = 7 cm (Ans.)
Hence, length of chord BC is equal to 7 cm .
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