Question

.

A point P is located outside the circle with centre O. A tangent from point P

touches the circle at A and a secant from P cuts the circle at B and C respectively.

PA =12cm PC= 16cm. Find the length of chord BC.



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Answer 1

answer : 7

PA=12 PC=16 SO PB= 9 SO BC = 16-9 = 7

Answer 2

Solution :-

given that,

→ PA = Tangent = 12 cm

→ PC = Secant = 16 cm

So,

→ PA² = PB * PC { Secant tangent theorem }

→ 12² = PB * 16

→ PB = 144/16

→ PB = 9

So,

→ BC = PC - PB

→ BC = 16 - 9

→ BC = 7 cm (Ans.)

Hence, length of chord BC is equal to 7 cm .

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