A point P is moving on the curve y = 2x2. The x coordinate of P is increasing at the rate of 4 units per second. Find the rate at which the y coordinate is increasing when the point is at (2, 8).
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dx/dt=4 (given)
y= 2x^2
dy/dt= (4x)dx/dt
[dy/dt] at (x=2) =4×2×4=32 unit/sec
y= 2x^2
dy/dt= (4x)dx/dt
[dy/dt] at (x=2) =4×2×4=32 unit/sec
PatelRitnesh:
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A point P is moving on the curve y = 2x² .
it is given that, x coordinate of P is increasing at the rate of 4 units per second.
e.g., dx/dt = 4 unit/sec
we have to find the rate of y coordinate is increasing when the point is at (2,8)
differentiating curves with respect to t,
dy/dt = 4x dx/dt
at (2, 8) , dy/dt = 4 × 2 × 4 = 32 unit /sec
hence, rate of increasing of y - coordinate is 32 unit/second
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