a point P is moving with uniform angular speed along a circle of radius R the speed of its projection Q on the diameter will be?
A: V=ω√r^2 - x^2
B: V= ω^2 (r-x)
C: V=ω/r √r^2 - x^2
D: V= 1/ω √r^2 - x^2
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Answer:
The particle has only centripetal acceleration and no tangential acceleration
since it is moving with a uniform speed ωr around the circle .
Therefore , acceleration of the particle = ω
2
r
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