Question

a point P is the distance of 29 cm from the centre of a circle radius 20 cm find the length of the tangent drawn from P to the circle

Answer 1

$\huge \bf{ \red{hey}}$


$\huge{ \mathfrak{ \blue{here \: is \: answer}}}$

$\bf{given = }$

point p is at distance of 29 cm

and radius= 20 cm

$\bf{to \: find \: = }$

length of tangent.

now according to question


here we know that the radius makes 90° angle with tangent .

so we got a right angled triangle

now

we will use Pythagoras theorem.


$\sf{qp ^{2} = op ^{2} - oq ^{2} }$


$qp ^{2} = 29 ^{2} - 20 ^{2}$

$qp ^{2} = 841 - 400$

$\sf{qp ^{2} = 441}$

$\sf{qp = \sqrt{441}}$

$\bf{qp = 21 \: cm}$

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Answer 2

here is answer
$\sf{qp ^{2} = op ^{2} - oq ^{2} }$


$qp ^{2} = 29 ^{2} - 20 ^{2}$

$qp ^{2} = 841 - 400$

$\sf{qp ^{2} = 441}$

$\sf{qp = \sqrt{441}}$

$\bf{qp = 21 \: cm}$


hope it help you

thanks