A point p lay on a line that is parallel to the x axis and three units below it p is twice as far from q(6,2) as from the origi .find the coordinates of p.
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the coordinates of p = (1.5 , - 3)
Step-by-step explanation:
A point p lay on a line that is parallel to the x axis and three units below it
=> p = ( x , - 3)
p is twice as far from q(6,2) as from the origin
p Distance from origin = √(x - 0)² + (-3 - 0)²
= √(x² + 9)
p Distance from q(6,2) = √(x - 6)² + (-3 - 2)²
= √((x - 6)² + 25)
√((x - 6)² + 25) = 2√(x² + 9)
=> (x - 6)² + 25 = 4(x² + 9)
=> x² - 12x + 36 + 25 = 4x² + 36
=> 3x² + 12x - 25 = 0
=> x ≈ 1.5
p = (1.5 , - 3)
Distance from origin = 3.35
Distance from (6 , 2) = 6.7
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