A point P on the trajectory of the projectile projected at an angle theta with the horizontal subtends an angle alpha and beta are the point of projection and point of landing
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tan α + tan β = tan θ
Explanation:
Given: A point P on the trajectory of the projectile projected at an angle θ with the horizontal subtends an angle α and β are the point of projection and point of landing.
Solution:
We find that the external angle θ are can be expressed in terms of the internal angles α and β as follows:
tan α + tan β = tan θ
Tangent of the angle θ formed by the projectile with the horizontal = Sum of tangents of the angles subtended by the horizontal at point of projection and point of landing.
Option 2 is the answer.
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Answer: option 2 is correct
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