A point particle of mass 1.0 gm is revolving on a circle of diameter 8 cm. Its moment of inertia is:
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Answer:
0.008 is answer thank you
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GIVEN :
r = 8 cm = 0.8 m
m = 1 gm = 0.001 kg
Formula =
I = mr²
I = 0.001 × (0.8)²
I = 0.001 × 0.64
I = 0.00064 kg-m²
moment of inertia = 0.00064 kg-m²
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