Question

a point R with x-coordinate 6 lies on the line segment joining the points P(2,-3,4)and Q(8,0,10)Then distance between of R origin is​

Answer 1

Answer:

$\sqrt{101}$

Step-by-step explanation:

suppose take the ratio m:n as k:1

now from section formulae

⇒R=$\frac{8k+2}{k+1}$,$\frac{-3}{k+1}$,$\frac{10k+4}{k+1}$

⇒but we know that

x-co-ordinate of R=6

then,

⇒   $\frac{8k+2}{k+1}$=6

⇒8k+2=6k+6

⇒2k-4=0

⇒k=2

by substueting we get R=(6,-1,8)

then distance =$\sqrt{6^{2} +1^{2}+8^{2} }$

⇒$\sqrt{36+1+64}$=$\sqrt{101}$