A point source is emitting sound in all directions. Find the
ratio of distance of two points from the point source where
the difference in loudness levels is 3 dB. (log10 2 = 0.3)
(1) 2
(B)3
(C) 1/2
(D) 1/2
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Answer:
The answer will be 1/√2
Explanation:
According to the problem there is a point source which emitting sound.
Now there are two points from the point source.
Now we know that loudness , β = 10 log I/I0
where I = K/r^2 means I is inversely proportional to r^2
Therefore, β = 10 log K/r^2/I0
= 10 log K/r^2I0
= 10 { log k' - 2 log r}
As it is a constant statement we can write,
β1= 10 { log k' - 2 log r1}
β2= 10 { log k' - 2 log r2}
Now the difference in loudness is given as 3 dB
Therefore ,
β1 - β2 = 10 [ 2 log (r2/r1)]
=> 3 = 10 log (r2/r1)^2
=> 0.3 = log (r2/r1)^2
=> 2 = (r2/r1)^2
Therefore , r1=r2 = 1 /√2
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