A point source is located at a distance of 20 cm from the front surface of a glass by a concave lens the lens has a thickness of 5 centimetre and radius of curvature of a surface is 5 into metre
Answers
We need the radii of surfaces of lens R1 and R2. I am giving the formulas and the procedure here. So follow these steps.
1) Formulas:
Back Effective focal length to focus F' = B EFL = f ' (+ve)
Effect focal length in front of the front surface = EFL = f (-ve)
R1 = +ve R2 = -ve
Thickness of the lens = d
μ = refractive index of the lens wrt air (medium) around the lens on both sides
Frontal focal length (distance) from surface to Focus F = FFL = -ve
Back Focal length (distance) from back surface to Focus F' = BFL = + ve
2. Given values:
Given R1 = R2, d = 5 cm, μ = 1.5 , u = - 20 cm
3. Procedure:
1) Find f = f'
2) Then find v from the formula 1/f = 1/v - 1/u
3) From v now subtract (f' - BFL) to get the distance of image from the rear surface. This value of (f ' - BFL) or (f - FFL) may be close to d/2.