A point source of light is at a depth 'h' from the surface of a liquid of refractive index 1.25. A disc is so placed on the surface of liquid that it blocks all light
coming out from the surface. If minimum diameter of the disc is 8 m, depth of the source below the surface (h) is
Options
6 m
3 m
4.2 m
8 m
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Answered by
0
Step-by-step explanation:
i don't know answer the question sorry
Answered by
0
Answer:
Correct option is
A
(μ
2
−1)
1/2
2h
The figure shows incidence from water at a critical angle θ
c
for the limiting case.
Now, sinθ
c
=
μ
1
so that tanθ
c
=
(μ
2
−1)
1/2
1
From figure, tanθ
c
=
h
r
where r is the radius of the disc.
∴ Diameter of the disc 2r =2htanθ
c
,d=
(μ
2
−1)
1/2
2h
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