A point source S is placed at a distance of 15 cm from a converging lens of focal length 10 cm on its.
principal axis. A diverging mirror of focal length 12 cm is placed so that a real image is formed on the
source itself. Determine the distance between lens and mirror in cm.
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Explanation:
Formula for refraction through the lens is,
u=−15cm and f=±10cm
v
1
+
15
1
=
10
1
v=30cm
As v is positive,the image I
1
,is formed to the right of lens.
The convex mirror is to be placed to the right of lens in such a way hat light rays fall on the mirror normally.
Then only the light rays will retrace their path and form final image on the object itself.
This shows that image I
1
formed by the lens should be at the center of curvature of the mirror i.e,PI
1
=R=2f=24cm
As ∣v∣=OI
1
=30cm. ,Hence OP=30−24=6cm
Thus,the convex mirror should be placed at a distance of 6cm to the right of lens
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