Question

A polar bear is swimming at an average speed of 2.6 how far will it have traveled after 10.0hours

Answer 1

$\huge{\underline{\underline{\red{\mathfrak{AnSwEr :}}}}}$

Given :

• Average Speed = 2.6 km/h
• Time (t) = 10 hours

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To Find :

• Distance Traveled

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Solution :

We have formula for Average Speed :

$\large {\boxed{\sf{Speed_{avg} \: = \: \dfrac{Distance}{time}}}} \\ \\ \implies {\sf{2.6 \: = \: \dfrac{Distance}{10}}} \\ \\ \implies {\sf{Distance \: = \: 2.6 \: \times \: 10}} \\ \\ \implies {\sf{Distance \: = \: 26 \: m}} \\ \\ {\underline{\sf{\therefore \: Distance \: traveled \: is \: 26 \: m}}}$

Answer 2

$\huge{\underline{\underline{\bf{Solution}}}}$

$\rule{200}{2}$

$\tt given\begin{cases} \sf{Time \: taken \: (t) = 10 \: hours} \\ \sf{Speed = 2.6 \: kmh^{-1}} \end{cases}$

$\rule{200}{2}$

$\Large{\underline{\underline{\bf{To \: Find :}}}}$

We have to find the Distance traveled.

$\rule{200}{2}$

$\Large{\underline{\underline{\bf{Explanation :}}}}$

We know the formula to find the value of distance.

$\Large{\star{\boxed{\rm{Distance = Speed \times time}}}}$

_______________[Put Values]

$\tt{\mapsto Distance = 2.6 \times 10} \\ \\ \tt{\mapsto Distance = \frac{26}{\cancel{10}} \times \cancel{10}} \\ \\ \tt{\mapsto Distance = 26 \: m}$