Question

A pole 10 m high cast a shadow 10 mlong on the ground. calculate the angle of elevation of sun?

Answer 1

AB = Height of pole = 10 m
BC = Height of shadow = 10 m
In triangle ABC,
$= > \tan \angle acb = \frac{ab}{bc} \\ = > \tan \angle acb = \frac{10}{10} \\ = > \tan \angle acb = 1 \\ = > \tan \angle \: acb = \tan 45 \degree \\ = > \angle acb = 45 \degree$
Therefore, Angle of elevation of the sun =
$45 \degree$