A pole 13 m high stands 12m away from a building which is 18m high. Find distance between top of the pole and top of the building?
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Answer :-
13 Meters is the distance between top of the pole and top of the building.
Explaination :-
Given :-
• Height of the pole : 13 m
• Distance of the pole from the building : 12 m
• Building's height : 18 m
To find :-
• The distance between top of the pole and top of the building.
Solution :-
• The solution could be found through Pythagorus Theorem.
• Refer the attachment
• The attachment has the distance between top of the pole and top of the building as ?
• The height will be 5m because
=> Building height - Pole height
=> 18 - 13
=> 5m
• The base is 12m because it's the distance.
• The distance between top of the pole and top of the building =
Base = 12m
Height = 5m
Hypotenuse = x
=>(Hypotenuse )² = ( Base ) ²+( Height )²
![= > {x}^{2} = {12}^{2} + {5}^{2} = > {x}^{2} = {12}^{2} + {5}^{2}](https://tex.z-dn.net/?f=%3D+%26gt%3B+%7Bx%7D%5E%7B2%7D+%3D+%7B12%7D%5E%7B2%7D+%2B+%7B5%7D%5E%7B2%7D)
![= > {x }^{2} = 144 + 25 = > {x }^{2} = 144 + 25](https://tex.z-dn.net/?f=%3D+%26gt%3B+%7Bx+%7D%5E%7B2%7D+%3D+144+%2B+25)
![= > {x}^{2} = 169 = > {x}^{2} = 169](https://tex.z-dn.net/?f=%3D+%26gt%3B+%7Bx%7D%5E%7B2%7D+%3D+169)
![= > x = \sqrt{169} = > x = \sqrt{169}](https://tex.z-dn.net/?f=%3D+%26gt%3B+x+%3D+%5Csqrt%7B169%7D)
![= > x = 13 = > x = 13](https://tex.z-dn.net/?f=%3D+%26gt%3B+x+%3D+13)
![\large{\green{\boxed{\green{\boxed{\red{\textsf{HYPOTENUSE = 13cm}}}}}}} \large{\green{\boxed{\green{\boxed{\red{\textsf{HYPOTENUSE = 13cm}}}}}}}](https://tex.z-dn.net/?f=%5Clarge%7B%5Cgreen%7B%5Cboxed%7B%5Cgreen%7B%5Cboxed%7B%5Cred%7B%5Ctextsf%7BHYPOTENUSE+%3D+13cm%7D%7D%7D%7D%7D%7D%7D)
The distance between top of the pole and top of the building is 13 m
13 Meters is the distance between top of the pole and top of the building.
Explaination :-
Given :-
• Height of the pole : 13 m
• Distance of the pole from the building : 12 m
• Building's height : 18 m
To find :-
• The distance between top of the pole and top of the building.
Solution :-
• The solution could be found through Pythagorus Theorem.
• Refer the attachment
• The attachment has the distance between top of the pole and top of the building as ?
• The height will be 5m because
=> Building height - Pole height
=> 18 - 13
=> 5m
• The base is 12m because it's the distance.
• The distance between top of the pole and top of the building =
Base = 12m
Height = 5m
Hypotenuse = x
=>(Hypotenuse )² = ( Base ) ²+( Height )²
Attachments:
![](https://hi-static.z-dn.net/files/d9a/9e09db24b4ab0a1c30eb8b301eb70fba.jpg)
![](https://hi-static.z-dn.net/files/dcd/ac7ce81de12d5d7a8aeb9890943f3212.jpg)
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