Question

A pole 13 m high stands 12m away from a building which is 18m high. Find distance between top of the pole and top of the building?

Answer 1

Answer :-

13 Meters is the distance between top of the pole and top of the building.

Explaination :-

Given :-

• Height of the pole : 13 m
• Distance of the pole from the building : 12 m
• Building's height : 18 m

To find :-

• The distance between top of the pole and top of the building.

Solution :-

• The solution could be found through Pythagorus Theorem.

• Refer the attachment

• The attachment has the distance between top of the pole and top of the building as ?

• The height will be 5m because

=> Building height - Pole height

=> 18 - 13

=> 5m

• The base is 12m because it's the distance.

• The distance between top of the pole and top of the building =

Base = 12m
Height = 5m
Hypotenuse = x

=>(Hypotenuse )² = ( Base ) ²+( Height )²

$= > {x}^{2} = {12}^{2} + {5}^{2}$

$= > {x }^{2} = 144 + 25$

$= > {x}^{2} = 169$

$= > x = \sqrt{169}$

$= > x = 13$


$\large{\green{\boxed{\green{\boxed{\red{\textsf{HYPOTENUSE = 13m }}}}}}}$

$\therefore$ The distance between top of the pole and top of the building is 13 m

Answer 2

Height of pole=13 m

Height of building=18 m

Distance between them=12 m

Now, we have to find the distance between the top of the pole and top of the building.

Now, there is a triangle formed at the top.

There, we have the base=12 m and perpendicular/height=

(18-13) m=5 m

So, we can find the distance between the tops/hypotenuse by "Pythagoras theorem".

=>c²=a²+b² (hypotenuse²=base²+perpendicular²/height²)

=>c²=12²+5²

=>c²=144+25

=>c²=169

=>c=√168

=>c=13

So, the distance between top of the pole and top of the building=13 m