A pole 20 m high casts a shadow of length 42.5 m. the height of the building, which casts a shadow of length 85 m under similar conditions will be : ( A ) 30 ( B ) 45 ( C ) 40 ( D ) 35
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Answer:
(draw the diagram accordingly)
- let the height of the pole 20 m be AB, shadow of the
- respective pole be BC=42.5
draw another pole of height PQ= x m
shadow QR=85 m
in ∆ABC
tan C = AC/BC
20/42.5
on simplified
=4/8.5
=40/85
the sun's angle of shadow casting will be equal for both the poles at the same time
therefore,
tan C= tan Q
40/85=PQ/85
PQ=40m
hope it was helpful
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