A pole 4.5 m high stands on level ground. It is supported in a vertical position by two wires attached to its top and to to the points on opposite sides of the pole each 3.2 m from the foot of the pole. How lomg wire has been used in both the sides?
Answers
Answer:
11 m
Step-by-step explanation:
The pole is vertical to the level ground and it is 4.5 m high.
Let us assume that AB is the pole with A at the bottom point and B at the top point.
Now, given that the pole is kept vertical by two wires placed each 3.2 m away from the base of the pole to the top of the pole.
Assume that BC is the wire on one side of the pole where C is the point on the ground.
So, it is clear from the given condition that, AC=3.2 m.
Hence, ΔABC is a right-angled triangle with ∠A=90°( as the pole is verticle to the ground), AB=4.5 m and AC= 3.2 m.
So, length of wire on one side of the pole, BC=√(AB²+AC²)
=√(4.5²+3.2²)
= 5.5217 m
Length of wire used on both sides of the pole being same.
Therefore, total length of wire used= 5.5217×2 = 11m (Approximate)
(Answer)