Question

A pole 5m high is situated on a horizontal surface . Sun rays are incident at an angle 30? What will be the size of shadow on horizontal surface?​

Answer 1

let the height of tower be AB = h m. let AD be the hoarding such that AD = 5 m

let C be the observation point. 

such that the angle of elevation of the top of the hoarding i.e. ∠BCD= 60 deg.

the angle of depression of the observation point C from A be ∠PAC=∠ACB = 45 deg.

therefore in the triangle ABC, 

in the triangle DBC,

Answer 2

Answer:

The size of shadow on horizontal surface is 10 m.

Explanation:

Given that,

Height of pole = 5 m

Angle = 30°

We need to calculate the size of shadow on horizontal surface

Using of figure

$AB=\dfrac{AC}{\sin\theta}$

Where, AB = size of shadow

AC = height of pole

Put the value in to the formula

$AB=\dfrac{5}{\sin30}$

$AB=10\ m$

Hence, The size of shadow on horizontal surface is 10 m.