Question

 A pole 6 m high casts a shadow 2√ 3 m long on the ground, then the Sun’s elevation is
(A) 60° (B) 45° (C) 30° (D) 90°
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Answer 1

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$tan \: theta = \frac{2 \sqrt{3} }{6 } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: \frac{1}{ \sqrt{3} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 30$

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c option is correct answers....

mark to brainly please...