a pole 6m high casts a shadow 2√3m long on the ground, then find the angle of elevation of sun.
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8
let @ angle of elevation of sun
tan@=height of pole /length of cast shadows
tan@ =6/2√3=√3
hence @=60°
tan@=height of pole /length of cast shadows
tan@ =6/2√3=√3
hence @=60°
Answered by
6
tan@=perpendicular \base
tan@=6\2√3
tan@=√3
tan@=60
tan@=6\2√3
tan@=√3
tan@=60
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