Question

a pole 6m high casts a shadow 2√3m long on the ground, then find the angle of elevation of sun.

Answer 1

Let height = 6m
length of shadow = 2√3m
ø is angle of elevation
Tanø= height/shadow length
= 6/2√3=√3
ø=π/3
Angle of elevation is =60°
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Answer 2

Answer:

The angle of elevation of sun is 60° when the pole is 6m high and casts a shadow of 2√3m  on the ground.

Step-by-step explanation:

To find: The angle of elevation of sun

Height of the pole = 6m

Length of shadow cast on ground = 2√3m

Let “θ be angle of elevation”.

According to the problem,

tan θ $=\frac{\text {Perpendicular}}{\text {Base}}=\frac{\text {Height of Pole}}{\text {Length} \text { of Shadow }}=\frac{6}{2 \sqrt{3}}=\sqrt{3}$

$\begin{array}{l}{\Rightarrow \tan \theta=\sqrt{3}} \\ {\therefore \theta=\tan ^{-1} \sqrt{3}=60^{\circ}}\end{array}$

Thus, “angle of elevation of sun = 60°”