Question

a pole 6m high casts a shadow of 2root3m. find the sun's altitude​

Answer 1

Answer....

Let height = 6mlength of shadow = 2√3mø is angle of elevationTanø= height/shadow length= 6/2√3=√3ø=π/3Angle of elevation is =60°

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Answer 2

Answer:

θ = 60°

Step-by-step explanation:

tanθ = AB/BC

        $= 6/2\sqrt{3}$

        $= 3/\sqrt{3}$

        $= \sqrt{3}$

        = tan 60°

∴  θ = 60°

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